Solving Quadratic Problems Involving Fractions

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Suppose you have a problem like:

eq001

The first thing you do is find out what the solution can't be so that you don't end up dividing by zero. In this example, that means neither (3x-2) nor (x+2) can be zero. So, x cannot be either 2/3 or -2 for a solution.

Once you've taken care of that, you cross-multiply to get (2x-5)(x+2) = (-4x-3)(3x-2) and proceed with the strategy for solving quadratics with brackets.

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